CDS 140a Winter 2013 Homework 1: Difference between revisions
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where $a$ is a constant. Sketch the phase portraits for $a = -1$, $a = 0$ and $a = 1$ and notice the qualitative structure of the phase portrait is the same for all $a < 0$ as well as for all $a > 0$, but that it changes at the parameter value $a = 0$, called a ''bifurcation value''. | where $a$ is a constant. Sketch the phase portraits for $a = -1$, $a = 0$ and $a = 1$ and notice the qualitative structure of the phase portrait is the same for all $a < 0$ as well as for all $a > 0$, but that it changes at the parameter value $a = 0$, called a ''bifurcation value''. | ||
</li> | </li> | ||
<li> '''Perko, Section 1.1, Exercise 6:''' | <li> '''Perko, Section 1.1, Exercise 6:''' | ||
<br> | |||
(a) If $u(t)$ and $v(t)$ are sollutions of the linear system | |||
\begin{align} | |||
\dot x = A x, | |||
\end{align} | |||
prove that for any constants $a$ and $b$, $w(t) = a u(t) + b v(t)$ is a solution. | |||
<br> | |||
(b) For | |||
\begin{align} | |||
A = \begin{bmatrix} 1 & 0 \\ 0 & -2 \end{bmatrix}, | |||
\end{align} | |||
find solutions $u(t)$ and $v(t)$ of $\dot x = A x$ such that every solution is a linear combination of $u(t)$ and $v(t)$. | |||
</li> | </li> | ||
<li> '''Perko, Section 1.2, Exercise 6:''' | <li> '''Perko, Section 1.2, Exercise 6:''' | ||
</li> | </li> |
Revision as of 18:25, 27 December 2012
R. Murray, D. MacMartin | Issued: 8 Jan 2013 |
ACM 101/AM 125a/CDS 140a, Winter 2013 | Due: 15 Jan 2013 |
__MATHJAX__
Note: In the upper left hand corner of the second page of your homework set, please put the number of hours that you spent on this homework set (including reading).
- Perko, Section 1.1, Exercise 3: Find the general solution of the linear system \begin{align} \dot x_1 &= x_1 \\ x_2 &= a x_2 \end{align} where $a$ is a constant. Sketch the phase portraits for $a = -1$, $a = 0$ and $a = 1$ and notice the qualitative structure of the phase portrait is the same for all $a < 0$ as well as for all $a > 0$, but that it changes at the parameter value $a = 0$, called a bifurcation value.
- Perko, Section 1.1, Exercise 6:
(a) If $u(t)$ and $v(t)$ are sollutions of the linear system \begin{align} \dot x = A x, \end{align} prove that for any constants $a$ and $b$, $w(t) = a u(t) + b v(t)$ is a solution.
(b) For \begin{align} A = \begin{bmatrix} 1 & 0 \\ 0 & -2 \end{bmatrix}, \end{align} find solutions $u(t)$ and $v(t)$ of $\dot x = A x$ such that every solution is a linear combination of $u(t)$ and $v(t)$. - Perko, Section 1.2, Exercise 6:
- Perko, Section 1.3, Exercise 5, parts a, c, e:
- Perko, Section 1.3, Exercise 6 (for part a, use 5a, 5c, 5e):
- Perko, Section 1.4, Exercise 4:
- Perko, Section 1.4, Exercise 6:
- Perko, Section 1.5, Exercise 4:
- Perko, Section 1.5, Exercise 9:
- Perko, Section 1.6, Exercise 2:
Notes:
- The problems are transcribed above in case you don't have access to Perko. However, in the case of discrepancy, you should use Perko (third edition) as the definitive source of the problem statement.
- There are a number of problems that can be solved using MATLAB. If you just give the answer with no explanation (or say "via MATLAB"), the TAs will take off points. Instead, you should show how the solutions can be worked out by hand, along the lines of what is done in the text book. It is fine to check everything with MATLAB.
- For numerical calculations, it is OK to use MATLAB to invert a matrix. But you should not use it to compute the matrix exponential and just put down the answer. Instead, show how to get the matrix exponential into a form in which the calculation can be done by hand (similar to what was done in lecture on 6 Jan) and then carry out the computation.
- For phase portraits, you should generate the diagram by hand and make sure to label any important features. Describe why the portrait looks as it does based on the relevant properties of the dynamical system (eg, eigenvalues of the A matrix).
- For the final exam, you will not be allowed to use MATLAB, so make sure you understand what you are computing and drawing!